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Distance between 1,3 and -3, -1

User Marius B
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\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ 1 &,& 3~) % (c,d) &&(~ -3 &,& -1~) \end{array}~~~ % distance value d = √(( x_2- x_1)^2 + ( y_2- y_1)^2) \\\\\\ d=√((-3-1)^2+(-1-3)^2)\implies d=√((-4)^2+(-4)^2) \\\\\\ d=√(32)\implies d=√(16\cdot 2)\implies d=√(4^2\cdot 2)\implies d=4√(2)
User Frederik Ziebell
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