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39 votes
39 votes
Can you help me solve me this math problems?

1. 200 - 7/21
2. 50 - 4/7
3. 24 1/4 - 20 3/5
4. 10 5/8 - 6 4/9
5. 6 1/2 - 5 3/4

User Wrtsprt
by
2.3k points

1 Answer

25 votes
25 votes

Explanation:

1.

200 - 7/21 = (200×21 - 7)/21 = (4200 - 7)/21 =

= 4193/21 = 599/3 = (199×3 + 2)/3 =

= 199 2/3

we could have seen that 7/21 = 1/3.

so, then this problem was

200 - 1/3 = (200×3 - 1)/3 = 599/3 = 199 2/3

(see above)

2.

50 - 4/7 = (50×7 - 4)/7 = (350 - 4)/7 =

= 346/7 = (49×7 + 3)/7 = 49 3/7

3.

24 1/4 - 20 3/5 = (24×4 + 1)/4 - (20×5 + 3)/5 =

= 97/4 - 103/5

to calculate this we need to bring both fractions to the save denominator. the LCM (lowest common multiple) of 4 and 5 is 20.

so,

97/4 - 103/5 = (97×5)/(4×5) - (103×4)/(5×4) =

= 485/20 - 412/20 = 73/20 =

= (3×20 + 13)/20 = 3 13/20

4.

10 5/8 - 6 4/9 = (10×8 + 5)/8 - (6×9 + 4)/9 =

= 85/8 - 58/9

the LCM of 8 and 9 is 72.

85/8 - 58/9 = (85×9)/(8×9) - (58×8)/(9×8) =

= 765/72 - 464/72 = 301/72 =

= (4×72 + 13)/72 = 4 13/72

5.

6 1/2 - 5 3/4 = (6×2 + 1)/2 - (5×4 + 3)/4 =

= 13/2 - 23/4

the LCM of 2 and 4 is 4.

13/2 - 23/4 = (13×2)/(2×2) - 23/4 =

= 26/4 - 23/4 = 3/4

User Ali Bahrami
by
3.1k points