Question

I need help plssssssssssddd

Answer 1

see explanation

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

(a)

calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (- 3, 0) and (x₂, y₂ ) = (0, - 2) ← 2 points on the line

m =
`(-2-0)/(0-(-3))` =
`(-2)/(0+3)` = -
`(2)/(3)`

(b)

the y- intercept is the point on the y- axis where the line crosses, that is

y- intercept c = - 2

(c)

y = -
`(2)/(3)` x - 2 ← equation of line