Question

What is the quotient? n+3/2n-6 divide n+3 /3n-9

Answer 1

(n+3)/(2n-6):(n+3)/(3n-9)=(n+3)/(2(n-3))×(3(n-3))/(n+3)=3/2

Answer 2

ANSWER
The quotient simplifies to

`(3)/(2)`



Step-by-step explanation


We want to find the quotient:


`(n + 3)/(2n - 6) / (n + 3)/(3n - 9)`


We need to multiply the first fraction by the reciprocal of the second fraction to obtain,


`\Rightarrow (n + 3)/(2n - 6) / (n + 3)/(3n - 9) = (n + 3)/(2n - 6) * (3n - 9)/(n + 3)`



We now factor to obtain,


`\Rightarrow(n + 3)/(2n - 6) / (n + 3)/(3n - 9) = (n + 3)/(2(n - 3)) * (3(n - 3))/(n + 3)`


We cancel out common factors to obtain,




`\Rightarrow(n + 3)/(2n - 6) / (n + 3)/(3n - 9) = (1)/(2) * (3)/(1)`


This finally gives us,


`(n + 3)/(2n - 6) / (n + 3)/(3n - 9) = (3)/(2)`