Answer:
After 35 years balance in the account = $93429.71
Step-by-step explanation:
We will applying the compound interest formula.
A =

Where,
A = the future value of the investment/loan, including interest
P = the principal investment amount (the initial deposit or loan amount)
r = the annual interest rate (decimal)
n = the number of times that interest is compounded per year
t = the number of years
Given that,
P = $6000
r = 8% =
= 0.08
n = 2 (because of twice in a year)
t = 35 years

A = 6000

A= $93429.71 (Option D)