Question

The atomic radius of carbon is 77 pm, and the atomic radius of sulfur is 103 pm. What is the circumference of each atom?

Answer 1

The atomic radius of carbon is 77 pm, and the atomic radius of sulfur is 103 pm. What is the circumference of each atom?

ANSWER

CARBON - 483.56

SULFUR - 646.84

FORMULA

`c \: = 2\pi\:r`

CARBON

C = 2(3.14)(77)

C = 6.28 × 77

= 483.56

SULFUR

C = 2(3.14)(103)

C = 6.28 × 103

= 646.84

Answer 2

Circumference of carbon = 483.56 pm

Circumference of sulphur = 1111.56 pm

Step-by-step explanation:

The circumference is the length of any great circle, the intersection of the sphere with any plane passing through its centre.

For carbon atom:

Atomic radius = 77 pm

Circumference = 2πr

=2 X 3.14 X 77

=154 X 3.14

Circumference of C = 483.56 pm

For sulphur:

Atomic radius = 177 pm

Circumference = 2πr

=2 X 3.14 X 177 pm

=1111.56 pm

Circumference of sulphur = 1111.56 pm

Hence,

The circumference of Carbon is 483.56 and the circumference of sulphur is 1111.56 pm.