Answer:
number of markers Camden has =
![5](https://img.qammunity.org/2019/formulas/mathematics/middle-school/plm5y63f6h2m4svxq8ugvlwsf5gairgi65.png)
number of markers Carly has =
![25](https://img.qammunity.org/2019/formulas/mathematics/middle-school/3l822w5pqu3786bxqa5nvdcjyvdazxzv5h.png)
Explanation:
Let the number of markers Camden has = x
now it is given that Carly has 5 times as many markers as Camden has
Number of markers Carly has = 5 ( number of markers Camden has )
=
![5x](https://img.qammunity.org/2019/formulas/mathematics/college/c6rhmx12uugilf9e9yqpe8za0il3kvk053.png)
now the total number of markers = 30
number of markers with Carly + number of markers with Camden = 30
so we have
( adding like terms x and 5x)
( dividing both sides by 6)
![x= 5](https://img.qammunity.org/2019/formulas/mathematics/middle-school/jt6uvdkc82vt1fdnum7ttohaze1gm0mset.png)
hence we have
number of markers Camden has =
![x=5](https://img.qammunity.org/2019/formulas/mathematics/college/m3atvlkke09t7u8nz2kzldrh2p4btreb3b.png)
number of markers Carly has =
![5x= 5(5) = 25](https://img.qammunity.org/2019/formulas/mathematics/high-school/1c0bxvx8jkb4grreyiy9iz04lzdvxdluki.png)