Solve for k j= k^2/4

asked Jul 15, 2019 228k views

0 votes

Solve for k

j= k^2/4

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7 votes

Answer:

k = +- 2sqrt(J)

Explanation:

This is the correct answer, I just took the test and this is right!

Harkl answered Jul 17, 2019

by Harkl

5.4k points

2 votes

j=k^2/4
4j=k^2
k=sqrt(4j) or (4j)^1/2

KidA answered Jul 22, 2019

by KidA

5.9k points

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