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Part 1.] Determine the equation of the inverse of
y= (1)/(4) x^(3) -2

A.]
y= \sqrt[3]{4x+2}
B.]
y= \sqrt[3]{4x-2}
C.]
y= \sqrt[3]{4x+8}
D.]
y= \sqrt[3]{4x-8}
E.]
y= \sqrt[3]{ (1)/(4)x-2}

Part 2.] Determine the equation of the inverse of
y=e^(x+3) -4.
A.]
y=ln(x+4)-3
B.]
y=ln x+1
C.]
y= (1)/(3)( (x)/(e)+4)
D.]
y= (1)/(4)lnx-3

User Phcaze
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1 Answer

2 votes
y = 1/4 x^3 + 2
1/4 x^3 = y - 2
x^3 = 4(y - 2)

x = cube root (4y - 8)

inverse y = cube root (4x - 8)

Its D.
User Rico Ocepek
by
8.1k points

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