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I really need help with this question. I have been trying for hours and no one has helped me.

A toy rocket is launched from a platform 29 feet above the ground at a speed of 79 feet per second. The height of the rocket in feet is given by the polynomial −16t^2 + 79t + 29, where t is the time in seconds. How high will the rocket be after 3 seconds?

User Mulli
by
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2 Answers

3 votes
Sorry, need to edit it.

= -144 + 237 + 29
= 122ft
User Yogeshwar
by
5.7k points
3 votes
h=-16*3^2+79*3+29
h= -144+237+29= 122 ft