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In a hydraulic system, piston 1 has a surface area of 100 cm2, and piston 2 has a surface area of 900 cm2. A force of 150 N is exerted on piston 1 of the hydraulic lift. What force will be exerted on piston 2?

User Fozia
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1 Answer

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From Pascal's law, we can say that the pressure exerted by piston 1 on the fluid will be transmitted with equal intensity to piston 2:

p_1 = p_2 (1)

The relationship between the pressure applied p, the force applied F and the surface A is

p= (F)/(A)

So we can rewrite (1) as

(F_1)/(A_1)= (F_2)/(A_2)
And from this, we can find the magnitude of the force exerted on piston 2, F2:

F_2 = A_2 (F_1)/(A_1)=(900 cm^2) (150 N)/(100 cm^2)=1350 N
User AnirbanDebnath
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