Question

Which translation maps the graph of the function f(x)=x^2 onto the function g(x)=x^2-6x+6

Answer 1

write x²-6x+6 into vertex form by completing a perfect square:
x²-6x+9+6-9=(x-3)²-3
compared with f(x)=x², g(x)=(x-3)²-3 is shifted three units to the right and three units down.

Answer 2

Translation from (0,0) to (3,-3), 3 units down, and 3 units to the right.

Explanation:

The Geometric Transformation called Translation of this parabola f(x)=x² is obtained, firstly by shifting it down 3 units simply adding -3 units as the independent term.

The Translation of the Parabola is counted by its vertex. y=x² (0,0) to y=x²-6x+6 (3,-3).

Algebraically:

So, f(x)=x² -3

Looking at g(x)=x²-6x+6, we still need to make it down after the curve intercept y-axis. b<0

Then, let's shift it three units to the right so its vertex hit the point 6, as y-coordinate, we have to add -3. If we want to add to the right sum negative value, then square it:

y= (x-3)²-3

y=x²-6x+9-3

y=x²-6x+6