Question

Part 1.] Which of the following is the inverse of the given function?


`y= 3 x^(5)-4`
A.]
`y= \sqrt[5]{ (x+3)/(4)}`
B.]
`y= \sqrt[5]{ (x-4)/(3)}`
C.]
`y= \sqrt[3]{ (x+4)/(5)}`
D.]
`y= \sqrt[5]{ (x+4)/(3)}`

Part 2.]  What is the inverse of the function 


`y=3 e^(-4+1)`?
A.]
`y= (1-log(x-3))/(4)`
B.] 
`y= (1-log( (x)/(3)))/(4)`
C.] 
`y= (1-ln(x-3))/(4)`
D.] 
`y= (1-ln( (x)/(3)))/(4)`

Answer 1

1. I believe the answer is D, y = fifth root of (x+4)/3
y = 3x⁵ - 4
Interchanging x and y
x = 3y⁵ - 4
solving for y in the equation; x=3y⁵-4
y = ((x+4)/3)^1/5

= ((x+4)/3)^1/5

2. inverse of the equation y = 3e^-4x+1
I think the answer is D;
Interchanging the variables x and y
x= 3e^-4y-1
Solving for y in x = 3e^-4y +1
y= -(In(x/3)-1)/4
= (1-In(x/3))/4