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1. find the equation of the circle with center at (-3,1) and through the point (2,13)

2. what is the equation of the circle with the center at (2,4) and the radius of 6.

(show all work please and thank you)

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Try this solution:
Common view of the equation of the circle is (x-a)²+(y-b)²=r², where point (a;b) is centre of the circle, r - radius.
1. using the coordinates of the centre and point (2;13) it is possible to define the radius of the circle: r=√(5²+12²)=13;
the equation is (x+3)²+(y-1)²=13² or (x+3)²+(y-1)²=169;
2. using the coordinates of the centre and the radius: (x-2)²+(y-4)²=6² or (x-2)²+(y-4)²=36.
User Grapefruitmoon
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