Question

Identify the vertical asymptote(s) of each function. Check all of the boxes that apply. f(x)=x-8/x^2-3x+2

x = -8


x = -2


x = -1


x = 1


x = 2


x = 8

Nevermind the answer was x=1 and x=2. If anyone is wondering how to do it you can put the denominator in desmos and where the 2 points hit the x axis is your answer.

Answer 1

x=1 and x=2

Explanation:

Answer 2

Since the function is:

`(x-8)/( x^(2) -3x+2)`

Now factorize the denominator:

`(x-8)/( x^(2) -x-2x+2)`


`(x-8)/( x(x-1) -2(x-1 ) )`


`(x-8)/( (x-1) (x-2 ) )`

Now put the denominator equals to zero:


`(x-1) (x-2 ) = 0`

Now take each one of them separately to find the vertical asymptotes:

`x-1 =0, x-2=0`

Ans: So there are TWO asymptotes:
1) x = 1.
2) x = 2.

-i