212k views
4 votes
A merry-go-round is spinning at a rate of 4.0 revolutions per minute. cora is sitting 1.0 m from the center of the merry-go-round and cameron is sitting right on the edge, 2.0 m from the center. what is the relationship between the rotational speeds of the two children?

User Eriophora
by
5.5k points

2 Answers

4 votes

Answer:

Same.

Step-by-step explanation:

The rotational speed of an object is given by :


\omega=(\theta)/(t)


\theta is the angular displacement

t is the time taken

The angular speed of a merry- go- round is 4 revolutions per minute. There are two persons Cora and Cameron. Cora is sitting 1.0 m from the center of the merry-go-round and Cameron is sitting right on the edge, 2.0 m from the center.

The rotational speeds of both of the children remains the same because it is independent of the distance from the center.

User Cytinus
by
5.9k points
2 votes
The rotational speed of the two children is the same.
In fact, it is defined as

\omega = (\Delta \theta)/(\Delta t)
where
\Delta \theta is the angle covered in the time
\Delta t. As it can be seen, this quantity does not depend on the distance from the centre, so the rotational speed is 4.0 revolutions per minute for both children.
User Jakemingolla
by
6.2k points