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Write the equation of the line that passes through the points (−8,−9) and (3,−4). Put your answer in fully simplified point-slope form, unless it is a vertical or horizontal line.

User Ravit
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1 Answer

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(\stackrel{x_1}{-8}~,~\stackrel{y_1}{-9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-4}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-4}-\stackrel{y1}{(-9)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-8)}}} \implies \cfrac{-4 +9}{3 +8} \implies \cfrac{ 5 }{ 11 }


\begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-9)}=\stackrel{m}{ \cfrac{ 5 }{ 11 }}(x-\stackrel{x_1}{(-8)}) \implies {\large \begin{array}{llll} y +9= \cfrac{ 5 }{ 11 } (x +8) \end{array}}

User Wliao
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