First of all we can draw a parallel line to divide the figure into a triangle and a rectangle as shown in the figure. To find the area of our rectangle, remember that the area of a rectangle is length times width, so

. Since we know for our figure that the length and width of our rectangle are 13cm and 6cm respectively, lets replace those values in our formula to get its area:


Similarly, the area of a triangle is one half times base times height, so

. Since we know that our base is 8cm and our height 6cm, lets replace those values in our equation to find the area of our triangle:


Now the only thing left is add our areas:

We can conclude that the correct answer is
A. 102