Question

If v = 4.00 meters/second and makes an angle of 60° with the positive direction of the y–axis, what is the magnitude of vx?

Answer 1

This velocity vector could then be pointing up and to the right or up and to the left. Since we only want the magnitude of the x-axis velocity, it doesn't matter. In any case if there is a 60° angle from the y-axis means the sin of the angle gives the x-component. (Typically the angle is given with respect to the x-axis in which the sin gives the y-component)
For this case

`v_x=4sin(60)(m)/(s)=3.464 (m)/(s)`

Answer 2

3.46 m/s I just answered this question on a test I hope this helps :)