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How many diagonals are there in a quadrilateral? In a pentagon? In a hexagon? In an octagon? Explain your answer thoroughly. ANSWER RIGHT AWAY IF YOU KNOW THE ANSWER PLEASE!!!

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There is a formula you can use to find the number of diagonals for any polygon. It is n(n-3)/2, where n is the number of sides. So for a quadrilateral it would be 4(4-3)/2=2 diagonals, a pentagon or would be 5(5-3)/2=5, a hexagon 6(6-3)/2=9, and an octagon 8(8-3)/2=20.
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