Question

The table below shows the distance d(t) in feet that an object travels in t seconds:

t
(seconds)
d(t)
(feet)
3
126
4
224
5
350
6
504


What is the average rate of change of d(t) between 3 seconds and 5 seconds, and what does it represent?

Answer 1

Average change of d(t) between 3s and 5s=(d(5)-d(3))/(5-3)=(350-126)/2=224/2=112 ft/t. This represents the average speed of the object between 3s and 5s.