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The table below shows the distance d(t) in feet that an object travels in t seconds: t (seconds) d(t) (feet) 3 126 4 224 5 350 6 504 What is the average rate of change of d(t) between 3 seconds and 5 seconds,
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The table below shows the distance d(t) in feet that an object travels in t seconds:

t
(seconds)
d(t)
(feet)
3
126
4
224
5
350
6
504


What is the average rate of change of d(t) between 3 seconds and 5 seconds, and what does it represent?

User Krcools
by
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1 Answer

4 votes
Average change of d(t) between 3s and 5s=(d(5)-d(3))/(5-3)=(350-126)/2=224/2=112 ft/t. This represents the average speed of the object between 3s and 5s.
User Naresh Chennuri
by
6.4k points
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