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1 vote
How do you solve
6(3b + 5) = 2(6b - 21) and
10y - 4 = 2(5y - 2)?

User Btav
by
8.0k points

1 Answer

5 votes
1. First, you can divide both sides by 2 to make it easier to solve

3(3b + 5) = 6b - 21

Next, you can divide both sides by 3

3b + 5 = 2b - 7

Subtract both sides by 2b and 5

b = -12 is your answer

2. First, divide both sides by 2

5y - 2 = 5y - 2

It is clear these are the same equation, so there will be infinite solutions

Infinite solutions is the answer
User Jack He
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8.3k points