Question

A certain weak acid, ha, has a ka value of 6.0×10−7. calculate the percent ionization of ha in a 0.10 m solution.

Answer 1

For the purpose, we will use the equation for determining the dissociation constant from concentration and percent of ionization:

Kd = c × α²

α = √(Kd/c) × 100%

Kd = 6.0×10⁻⁷

c(HA) = 0.1M

α = √(6.0×10⁻⁷/0.1) × 100% = 0.23%

So, in the solution, the acid percent of ionization will be just 0.23%.