Register
How much heat energy is absorbed when 6.83 kg of water is heated from 10.0 0C to 47.0 0C. The specific heat of water is 4.184 J/g 0C.
184k views
4 votes
How much heat energy is absorbed when 6.83 kg of water is heated from 10.0 0C to 47.0 0C. The specific heat of water is 4.184 J/g 0C.

User Loraderon
by
6.0k points

1 Answer

5 votes
Heat energy= mass x specific heat x change in temperature
change in temperature=47.0=10.0= 37 degrees
convert mass in G = 6.83x1000=6830g
Heat energy is hence= 6830 x 4.184 j/g/degrees x 37=1057338.64 j or 1057.33864Kj

User Robwirving
by
6.6k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.3m questions

9.7m answers

Other Questions

How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Key facts of covalent bonding
How do you decide whether an observed property of matter is a physical or a chemical property?
Consider the unbalanced equation for the combustion of hexane: 2C6H14(g)+19O2(g)→12CO2(g)+14H2O(g) Determine how many moles of O2 are required to react completely with 7.9 moles C6 H14 .
Link Copied!