Question

How many milliliters of a 5.0 M H2SO4 stock solution would you need to prepare 108.0 mL of 0.45 M H2SO4?

Answer 1

To prepare 108.0 mL of a 0.45 M H2SO4 solution, you would need to measure 9.72 mL of the 5.0 M H2SO4 stock solution.

Step-by-step explanation:

To solve this problem, we can use the concept of dilution. The formula for dilution is C1V1 = C2V2, where C1 and V1 are the concentration and volume of the stock solution, and C2 and V2 are the concentration and volume of the diluted solution.

In this case, the given concentration of the stock solution is 5.0 M and the volume of the stock solution needed is unknown. The desired concentration of the diluted solution is 0.45 M and the volume of the diluted solution is 108.0 mL. Plugging in these values into the dilution formula will give us the volume of the stock solution needed.

Let's solve for V1:

(5.0 M)(V1) = (0.45 M)(108.0 mL)

V1 = (0.45 M)(108.0 mL)/(5.0 M)

V1 = 9.72 mL

Therefore, you would need to measure 9.72 mL of the 5.0 M H2SO4 stock solution to prepare 108.0 mL of 0.45 M H2SO4.

Answer 2

For the purpose we will use solution dilution equation:
c1xV1=c2xV2
Where, c1 - concentration of stock solution; V1 - a volume of stock solution needed to make the new solution; c2 - final concentration of new solution; V2 - final volume of new solution.
c1 = 5.00 M
c2 = 0.45 M
V1 = ?
V2 = 108 L
When we plug values into the equation, we get following:
5 x V1 = 0.45 x 108
V1 = 9.72 L