Question

Mass of 0.432 moles of C8H9O4?

Answer 1

Step-by-step explanation:

It is known that number of moles present in a substance is equal to the mass divided by molar mass.

Mathematically, No. of moles =
`\frac{mass}{\text{molar mass}}`

As it is given that number of moles are 0.432 moles and molar mass of
`C_(8)H_(9)O_(4)` is 169.15 g/mol.

Hence, calculate the mass of
`C_(8)H_(9)O_(4)` is as follows.

No. of moles =
`\frac{mass}{\text{molar mass}}`

0.432 mol =
`(mass)/(169.15 g/mol)`

mass = 73.072 g

Thus, we can conclude that the mass of 0.432 moles of
`C_(8)H_(9)O_(4)` is 73.072 g.

Answer 2

Find one mole
8 C = 8 * 12 = 96
9 H = 1 * 9 = 9
4 O = 4 *16 = 64
Total = 169

1 mol = 169 grams.
0.432 mol = x

1/0.432 = 169/x
x = 0.432 * 169
x = 73.0 grams