Answer:
Explanation:
There are 3 data sets given as
I) x 7 8 9 10 11 12 13 Total
Frequ 1 2 1 2 2 0 2
Mean dev|x-10|*f 3 4 1 0 3 0 6 17
II) x 7 8 9 10 11 12 13 Total
Frequ 2 3 0 0 1 1 3
Mean dev|x-10|*f 6 6 0 0 1 2 9 24
III) x 7 8 9 10 11 12 13 Total
Frequ 0 0 4 4 1 0 1
Mean dev|x-10|*f 0 0 4 0 1 0 3 8
Thus we find the middle one Jason has the highest deviation.