the complete question in the attached figure
we have
(2/3)x+(5/2)y=15 equation (I)
4x+15y=12 equation (2)
multiplying equation (1) by 6
6(2/3)x+6(5/2)y=6(15)--------------------- > 4x+15y=90 equation (3)
Subtracting equation (3) from equation (2) gives
4x+15y=90
4x+15y=12
-----------------
0x+0y=78------------ > 0=78
Therefore, a system of linear equation that has no solution results on two unequal numbers in both sides of the equation.
the answer is the option B) 0=26