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Factor to find the zeros of the function defined by the quadratic expression.
7x2 + 14x − 105

1 Answer

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Answer:

{-5, 3}

Explanation:

7 is a factor common to all three terms of this polynomial function. Thus, after the first attempt to factor it, we have 7(x^2 + 2x - 15). The quadratic factors into (x + 5)(x - 3). Setting these = to zero individually, we get

x + 5 = 0, or x = -5, and

x - 3 + 0, or x = 3

Thus, the zeros of the given f(x) =7x2 + 14x − 105 are {-5, 3}.

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