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2i^2 times (3i)^3 PLZ EXPLAIN HOW YOU GET THE ANSWER

User Greg Blass
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1 Answer

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Given:

2i^2 * (3i)^3
As
(3i)^3= 3^3 i^3 =27i^3
Multiply and add the exponents.
we get


54i^5 \\ As \ i^2=-1 \ i^5=i^2 * i^2 \ i =-1 * -1 * i =i
We get

54i^5=54i

Answer: 54i
User Dentex
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