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I^8+i^9+i^10
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User SteelBytes
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1 Answer

5 votes

Answer:

i

Explanation:

i^8+i^9+i^10

Factor out and i^8

i^8( 1+i+i^2)

Using the rule of 4

8/4 =2 with remainder 0 remainder 0 =1

remainder 1 = i

remainder 2 = -1

remainder 3 = -i

i^8 = 1

1 ( 1+i +i^2)

We know that i^2 = -1

(1+i+-1)

i

User J Atkin
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