Question

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Answer 1

The quadratic formula is

`x= (-b\pm √(b^2-4ac) )/(2a)`.

For the equation
`4x^2-3x+9=2x+1`, we must first convert it into standard form
`ax^2+bx+c=0`. We see it is
`4x^2-5x+8=0`. From this, our coefficients are
`a=4, b=-5` and
`c=8`.

We plug these coefficients into the quadratic formula.


`x= (-(-5)\pm√((-5)^2-4(4)(8)) )/(2(4)) \\ \\ \\ \\ x = (5\pm√(-103))/(8) \\ \\ \\ \\ x = (5\pm\ i√(103))/(8)`

The answer is C.