The question asks that you use algebra tiles to model and solve the equation

. I set up the scenario digitally (see attached image).
Whatever blocks you have on both sides you can cancel. So we cancel one

-block, and to take away the

-block, we balance the equation by putting a

-block on the other side. We are left with 2

-blocks equal to 6

-blocks. This is equivalent to 1

-bock equal to 3

blocks, so

.
Algebraically, you can write

.
I personally find the latter approach much easier, but I think the tiles are a nice way to conceptualize what you're doing.