Question

1/7-3(3/7n-2/7)
I need help solving this problem...

Answer 1

So we have

`(1)/(7)-3( (3)/(7n)- (2)/(7))`

The first step is to distribute the –3


`(1)/(7)+( (-3*3)/(7n)- (-3*2)/(7))`

Next, we simplify within the parentheses. In order to do this, we must have a common denominator.


`(1)/(7)+( (-9)/(7n)- (-6)/(7)* (n)/(n) ) \\ \\ \\ \\ (1)/(7)+( (-9)/(7n)- (-6n)/(7n) ) \\ \\ \\ \\ (1)/(7)+ (-9+6n)/(7n)`

Then, we find a common denominator again and simplify.


`(1)/(7)* (n)/(n) + (-9+6n)/(7n) \\ \\ \\ \\ (n-9+6n)/(7n) \\ \\ \\ \\ (7n-9)/(7n)`

And we're done. While it may be tempting to try to cancel 7n, this is not actually allowed. Try substituting in a non-zero number for n and you'll see why.

Answer 2

The answer is 1/7n + 32/21