Question

Algebraically prove that X^3+10/x^3+9=1+ 1/x^3+9 where x is not equal to -3

Answer 1

Algebraically prove that X^3+10/x^3+9=1+ 1/x^3+9 where x is not equal to -3

`(x^3+10)/(x^3+9)=1+(1)/(x^3+9) \\ \\ \\ (x^3+10)/(x^3+9)=((x^3+9)+1)/(x^3+9)\\ \\ \\ (x^3+10)/(x^3+9)=(x^3+10)/(x^3+9) \\ \\ \\x\in R \qquad x\in (-\infty, +\infty)`