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(x^2+3y-3) - (-2x^2+3y-1)

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(x^2+3y-3) - (-2x^2+3y-1)
Apply plus/minus rule.
-(-a)=a amd -(a)=-a

(x^2+3y-3) - (-2x^2+3y-1)=x^2+3y-3+2x^2-3y+1

=x^2+3y-3+2x^2-3y+1 \\ Add \ like \ terms \\ =3x^2 - 2 \\

Answer: \ 3x^2-2
User Rhangaun
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