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Helppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

Helppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp-example-1
User Edcs
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2 Answers

4 votes
x=((-3)+-√3²-4×5×(-4))/2×5
User Ttzn
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4 votes
We write the polynomial:
We have then:
5x ^ 2 + 3x-4 = 0
a=5
b=3
c=-4
Applying resolver we have
x = (- b +/- root (b ^ 2 - 4ac)) / (2a)
Substituting values:
x = (- (3) +/- root ((3) ^ 2 - 4 (5) (- 4))) / (2 (5))
Answer:
x = (- (3) +/- root ((3) ^ 2 - 4 (5) (- 4))) / (2 (5))
(option 1)
User Shrikant
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