Question

The diagonal of a triangle measures 18.2 inches. The width is 6.7 inches. What is the perimeter of the rectangle? (This has to do with Pythagorean Theorem)

Answer 1

Check the picture below.

`\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies √(c^2 - a^2)=b \qquad \begin{cases} c=\stackrel{hypotenuse}{18.2}\\ a=\stackrel{adjacent}{6.7}\\ b=opposite\\ \end{cases} \\\\\\ √(18.2^2 - 6.7^2)=b\implies √(286.35)=b\implies 16.92\approx b`