Question

To what potential should you charge a 0.900 μf capacitor to store 1.50 j of energy

Answer 1

The energy stored in a capacitor is given by

`U= (1)/(2) CV^2`
where C is the capacitance and V the voltage applied.
In our problem,
`C=0.900 \mu F=0.9 \cdot 10^(-6) F`, while the energy is
`U=1.5 j`. We can then solve the formula to find V:

`V= \sqrt{ (2U)/(C) }= \sqrt{ (2\cdot 1.5 J)/(0.9\cdot 10^(-6) F) }=1826 V`