Question

the elevation of Denver Colorado is 13 times greater than that of waikapu. hawaii.the sum of their elevations is 5600 ft. find the elevation of each city

Answer 1

400ft

Explanation:

Answer 2

Let
`x` be the elevation of Denver and
`y` the elevation of Waikapu. Since the elevation of Denver is 13 times greater than the elevation of Waikapu,
`x=13y`. We also know that the sum of their elevations is 5600 ft, so
`x+y=5600`. We have now tow equations we can solve to find both altitudes:

`\left \{ {{x=13y(1)} \atop {x+y=5600(2)}} \right.`
We can replace the value of
`x` from equation (1) in equation (2) to get:

`13y+y=5600`

`14y=5600`

`y= (5600)/(14)`

`y=400`
Now that we know the elevation of Waikapu, lets replace that value in equation (1) to get the elevation of Denver:

`x=13(400)`

`x=5200`

We can conclude that the elevation of Denver Colorado is 5200 ft, and the elevation of Waikapu Hawaii is 400 ft.