Answer:
Option A. 68.4 square units.
Explanation:
Since sides ED = EF = 13 units
So the given triangle is an isosceles triangle and in an isosceles triangle EFD, perpendicular drawn from E to DF, will be perpendicular bisector of DF.
Moreover, to this perpendicular bisector to DF will be the height of the triangle.
Now Area of a triangle of
× base × height.
Sin 63 =
=
![(h)/(13)](https://img.qammunity.org/2019/formulas/mathematics/high-school/7tos4rjq0bddhke1an0wpagl20vuqmbzf8.png)
h = 13 sin 63 = 13 ( 0.891) = 11.583 units
Cos 63 =
=
![(Base)/(13)](https://img.qammunity.org/2019/formulas/mathematics/high-school/k65244dlxc04nh8ay4clohxs87ttfbyhfp.png)
Base = 13 cos 63 = 13 × (0.454)
= 5.90 units
Since DF = 2 × base = 2 × 5.90
= 11.80 units
Now area of EDF =
× 11.80 × 11.583
= 68.86 ≈ 68.40 square units.
Option A. 68.4 square units.