For a simple harmonic motion energy is given with:
![E=(1)/(2)kA^2](https://img.qammunity.org/2019/formulas/physics/college/zbcj4ozgo7km0snmojw7h52swjzt7adpck.png)
Where k is a constant that depends on the type of the wave you are looking at and A is amplitude.
Let's calculate the energy of the wave using two different amplitudes given in the problem:
![E_1=(1)/(2)k(1)^2=(1)/(2)k\\E_2=(1)/(2)k(2)^2=(4)/(2)k=2k\\](https://img.qammunity.org/2019/formulas/physics/college/3vgx76b0k18pwfla9275eu6jipqndb3vgk.png)
We can see that energy associated with the wave is 4 times smaller when we decrease its amplitude by half. So the answer should be C.