Question

An athlete prepares to throw a 2.0-kilogram discus. His arm is 0.75 meters long. He spins around several times with the discus at the end of his out-stretched arm so that the discus reaches a velocity of 5.0 m/s. What is the centripetal force acting on the discus?

A.9.4 N
B.14 N
C.27 N
D.66 N

Answer 1

I am pretty sure the answer is "66N"

Step-by-step explanation:

I've seen a lot of results on the internet saying the same thing

If this is not the answer, I am truly sorry and you can message me so that I can delete the question.

Have a good day!

Answer 2

the centripetal force would be mv^2/r
which is then equal to 2*5*5/0.75
that's 66 N