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Find two consecutive even integers such that the smaller added to three times the larger gives a sum of 54

User Irpbc
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2 Answers

7 votes
Let's call x the smaller integer and x + 2 the larger one.


x+3(x+2)=54

x + 3x + 6 = 54

4x = 48

x= (48)/(4)=12

And
x+2=12+2=14

Hope this helps !

Photon

User Munish Chandel
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5 votes
Let n be the first even integer, and n+2 will be the second even integer. (Why? Think 2 and 4, 2+2=4. This is the case for every consecutive even integers).

n + 3(n+2) = 54
n + 3n + 6 = 54
4n = 48
n = 12, n+2 = 14
User Sqreept
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