2 Answers

Okarakose · Answer 1 · 2019-02-12T06:48:24+0000

Let original diameter be x
area =
$\pi (x/2)^(2)$

After the original diameter has increased by 50%
x = 1.5x
area =
$\pi (3x/4)^(2)$

changes in area =
$\pi (3x/4)^(2)$ -
$\pi (x/2)^(2)$
changes in area =
$\pi [(3x/4)^(2) -(x/2)^(2)]$
changes in area =
$\pi [9x^2/16 - x^2/4]$
changes in area =
$\pi [9x^2/16 - 4x^2/16]$
changes in area =
$\pi [5x^2/16]$

Change in area =
$\pi [5x^2/16]$ /
$\pi (x/2)^(2)$ x 100
Change in area =

x

x 100
Change in area = 5/4 x 100
Change in area = 125% (Answer D)

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