Question

Eli and Karl each throw a basketball straight up in the air at the same time. Eli is standing on a deck and the height of his ball, in meters, is given by the function f(x)=−4.9x2+12x+2.5 , where x is the number of seconds after the ball is released from his hands.

Karl is standing on the ground and the height of his ball, in meters, is given by the function g(x)=−4.9x2+14x , where x is the number of seconds after the ball is released from his hands.

There is a moment when the basketballs are at the same height.



What is this height?

Enter your answer, rounded to the nearest tenth of a meter, in the box.

Answer 1

The height at which both basketballs are at the same height is approximately 16.3 meters.

Step-by-step explanation:

To find the moment when the basketballs are at the same height, we need to find the common height value for both functions.

Setting the functions equal to each other, we get: -4.9x^2 + 12x + 2.5 = -4.9x^2 + 14x

Simplifying the equation, we get 2x = 2.5, which means x = 1.25.

Substituting this value back into the original function for Eli, we get f(1.25) = -4.9(1.25)^2 + 12(1.25) + 2.5 = 16.325

Therefore, the height at which both basketballs are at the same height is approximately 16.3 meters.

Answer 2

Just took the K12 quiz, and like killdrone said in the comments, the correct answer is 9.8 m

Step-by-step explanation: