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The line through (8, 0) with slope -3/4 in slope-intercept form

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\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ % (a,b) &&(~ 8 &,& 0~) \end{array} \\\\\\ % slope = m slope = m\implies -\cfrac{3}{4} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-0=-\cfrac{3}{4}(x-8) \implies y=-\cfrac{3}{4}x+6
User Zac Sprackett
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