Hey there! :D
So, I know this can be very, very confusing. I will try my best to explain this so it is understandable.
We need to start finding it by finding the slope of the line.
You can use the rise/run method, but I prefer to put it into this equation:
m=(y2-y1)/(x2-x1)
Plug in a pair of points on the line. (-2,0) and (0,-4)
m=(-4-0)/(0-(-2)
m=(-4-0)/(0+2)
m=-4/2
m=-2
The slope is -2.
So, plug that into point-slope form. Use slope for m, and (x1,y1) as a pair of points.
y-y1= m(x-x1)
y-(-4)= -2(x-0)
y+4=-2(x-0)
y+4= -2x
Now, lastly, we just need to put in in slope-intercept form.
y=mx+b
Subtract 4 on both sides.
y=-2x-4 <== equation of the line
I hope this helps!
~kaikers