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Help please! 10 points!

10: Gavin builds furniture for a living. he Sells chairs for $45 and tables for $70 each. It takes Gavin 4 hours and $10 worth of supplies to build each chair. A table requires 10 hours and $15 worth of supplies to make. Gavin wants to work for no more than 40 hours per week and spend no more than $80 on materials. Write a system of inequalities and state 3 possible combos.

1 Answer

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Let the number of chairs Gavin build per week is x and number of tables he builds per week is y.

It takes 4 hours to work on a chair and 10 hours to work on a table. So time taken to work on x chairs and y tables will be:


Time=4x+10y

Gavin wants to work for no more than 40 hours. So we can write the inequality as:


4x+10y \leq 40

It takes $10 worth of supplies to build a chair and $15 worth of supplies to build a table. So cost or worth of supplies for x chairs and y tables will be:


Cost=10x+15y

Gavin wants to spend no more than $80 on material. So we can write the inequality as:


10x+15y \leq 80

Thus the system of inequalities is:


4x+10y \leq 40


10x+15y \leq 80

We can observe the possible combinations from the graph of these inequalities, which is shown below:
a) 0 chair and 3 tables
b) 5 chairs and 2 tables
c) 8 chairs and 2 tables
Help please! 10 points! 10: Gavin builds furniture for a living. he Sells chairs for-example-1
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