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A gas has a pressure of 0.410 atm and volume of 32 L. At what pressure, would the volume of the gas change to 28 L

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The question here follows the ideal gas law, so we can say that the ideal gas equation is applicable which is PV = nRT
where:P is pressure,V is volume,n is number of moles, R is universal gas constant, andT is temperature.
When the right-hand side of the equation is constant, P₁V₁ = P₂V₂ this is the existing relationship,
Substituting the given will give us:(0.410 atm)(32 L) = (P₂)(28 L)P₂ = 0.4686
User Jim Lahman
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